[填空题]
A force of 10.0 ± 0.2 N is a5u jrln(g1:b xyb:d /kkk3b a1pplied to a mass of 2e/ xn2i c u-/;1vho8btgk bfy;.0 ± 0.01 kg, causing it to accelerate-1b2/ix /tfnc;heg 8kyuov ;b. What is the percentage uncertainty of its acceleration? % (do not include the percent sign in your result)
参考答案: 2.50
本题详细解析: The acceleration is calculat :xsl u/uezh0.ed using the formula: $$ a=\frac{F}{m} $$ so the percentage uncertainty on the acceleration is the sum of the percentage error on the force and on the mass. The percentage uncertainty on the force is: $$ \frac{0.2}{10.0} \times 100 \%=2 \% $$ The percentage uncertainty on the mass is:
$$ \frac{0.1}{2.0} \times 100 \%=5 \% . $$ Hence the percentage error on the acceleration will be $7 \%$.
Post time 2024-8-21 21:38:19