[填空题]
A force of 10.0 ± 0.2 N is applied to a c ;f wkq+h3lu.mass of 2.0 ± 0.01 kg, causing it tobki8 lds+ v83;k y zb6n(3izrsmw)3x u accelerate. What is the percentage uncertainty s v +bmi3(38ksl8zu; xdn6 kzb)wri3yof its acceleration? % (do not include the percent sign in your result)
参考答案: 2.50
本题详细解析: The acceleration is calculated using the fo 3f* ai ;v*+biuk0s- cis g:bk0,htaeormula: $$ a=\frac{F}{m} $$ so the percentage uncertainty on the acceleration is the sum of the percentage error on the force and on the mass. The percentage uncertainty on the force is: $$ \frac{0.2}{10.0} \times 100 \%=2 \% $$ The percentage uncertainty on the mass is:
$$ \frac{0.1}{2.0} \times 100 \%=5 \% . $$ Hence the percentage error on the acceleration will be $7 \%$.