[填空题]
The density of a solid sphere is tuisg t 6tt4o6x; 2no3measured with percen82u6i.q v0e 3ov rlk xr*2uqmgtage uncertainty of 5%. The radius of the sphiqqmgur3 k 2ue.v0r*2ol6 8vx ere is 4.0 ± 0.2 cm. What is the percentage uncertainty in the mass of the sphere? % (Please do not include the % simbol in the blank)
参考答案: 20.0
本题详细解析: The mass of the sphere can be calculated by multiplying n0 dw;ejl:7lzu8 iti9z1wl m. its volume by the density of:wdzllt19;8uijl n.w 0 im7ze the material of which it is made: $$M=\frac{4}{3} \pi r^3 \rho$$ so the percentage uncertainty in $M$ is $$\frac{\Delta M}{M}=3 \frac{\Delta r}{r}+\frac{\Delta \rho}{\rho} .$$ The percentage uncertainty in $r$ is $5 \%$, so the percentage error in $M$ is $(3 \times 5 \%)+5 \%=20 \%$
Post time 2024-8-21 21:38:19