[填空题]
The potential differeb)6hi. sfxbr8tp+6hfs*9 , mxzz w-j fqzq/b e;o,ghq w(q 07ince ($V$) across a resistor is measured with a digital voltmeter to be $0.10 \; V$ . What is the percentage uncertainty in $V^2$ ? % (please only input numerical value without units and without the $\pm$ symbol.)
参考答案: 20.00
本题详细解析: The voltmeter is a digital device and so the uncertaig2mrd4 :4d1 0oimclsk6cvv m ,nty is the smallest value which i0 golmvr:s4 cm1 d2dv6,i cmk4t can record, $0.01 \mathrm{~V}$. This is a $10 \%$ uncertainty on the $0.10 \mathrm{~V}$ measurement. The uncertainty in $V^2$ will be twice this, giving $20 \%$.
Post time 2024-8-21 21:38:19