[填空题]
The potential differe3o8pjq wd7du9( v k;zco21lw t-y j 6,bry3abhnce ($V$) across a resistor is measured with a digital voltmeter to be $0.10 \; V$ . What is the percentage uncertainty in $V^2$ ? % (please only input numerical value without units and without the $\pm$ symbol.)
参考答案: 20.00
本题详细解析: The voltmeter is a digital device and so the uncertainty is the smallest wro.t8hft 3n1value which it can r1or3twn 8f.h tecord, $0.01 \mathrm{~V}$. This is a $10 \%$ uncertainty on the $0.10 \mathrm{~V}$ measurement. The uncertainty in $V^2$ will be twice this, giving $20 \%$.
Post time 2024-8-21 21:38:19