[填空题]
A force of 10.0 ± 0.2 N wm*.eqdz0x e ip 2rua40, hcc/is applied to a mass of 2.0 ± 0.01 kg, causing it cuj0g0oyq: oyjo* ;q 9s.j4 fzto acceu:9;4ocg. jzoqyjf y0j* o sq0lerate. What is the percentage uncertainty of its acceleration? % (do not include the percent sign in your result)
参考答案: 2.50
本题详细解析: The acceleration is calculated using the formula: no ckx ocvb4kuw7 /q3*w*1p r.$$ a=\frac{F}{m} $$ so the percentage uncertainty on the acceleration is the sum of the percentage error on the force and on the mass. The percentage uncertainty on the force is: $$ \frac{0.2}{10.0} \times 100 \%=2 \% $$ The percentage uncertainty on the mass is:
$$ \frac{0.1}{2.0} \times 100 \%=5 \% . $$ Hence the percentage error on the acceleration will be $7 \%$.