[填空题]
The density of a solid sphere is m49w23 d yo mzkqg;95n/xcgyef e fhm42yj4e5;vyz6 t lt b,-1( bbrjyj pdul42kasured with percentage uncertainty of 5%. The radius of the sphere is 4.0 ± 0 2lbmlfzbyt; vhr 2pkb uy44-65jd4j(,j 1et y.2 cm. What is the percentage uncertainty in the mass of the sphere? % (Please do not include the % simbol in the blank)
参考答案: 20.0
本题详细解析: The mass of the sphere can be calcudoj*3. 4eaht zlated by multiplying its volume by the density of the material of which 4azt.e d3oj* hit is made: $$M=\frac{4}{3} \pi r^3 \rho$$ so the percentage uncertainty in $M$ is $$\frac{\Delta M}{M}=3 \frac{\Delta r}{r}+\frac{\Delta \rho}{\rho} .$$ The percentage uncertainty in $r$ is $5 \%$, so the percentage error in $M$ is $(3 \times 5 \%)+5 \%=20 \%$