[填空题]
The potential differ ;lsr m ey fe8298gl7omzvr-o5b2hh n7ecng d 9v :vsrx.wc4j/+nce ($V$) across a resistor is measured with a digital voltmeter to be $0.10 \; V$ . What is the percentage uncertainty in $V^2$ ? % (please only input numerical value without units and without the $\pm$ symbol.)
参考答案: 20.00
本题详细解析: The voltmeter is a digital device and so the uncertsm*0k)c n zrfw jm*va.:8 ;f 2talny.dainty is the smallest value which it ca n..rn 0v*j flz: dka;tma*y8)fwm2csn record, $0.01 \mathrm{~V}$. This is a $10 \%$ uncertainty on the $0.10 \mathrm{~V}$ measurement. The uncertainty in $V^2$ will be twice this, giving $20 \%$.