[单选题]
The diagram below shows an arrange
app;vh .p u ws9z0)n9ni+ 2vwrment used to investigate d
4*+c y.eq)l/xz zwos ex:0l ubouble slit interfere
oxu*0czewez s)b+l.l/:qxy 4nce using microwaves.
The diagram below shows the view from above:
The microwaves from the transmitter are polarised. These waves are detected by the aerial in the microwave detector (probe). The aerial is a vertical metal rod.
The detector is moved along the dotted line UY. As it is moved, maximum and minimum signals are detected. Maximum signals are first detected at points $\mathrm{V}$ and $W$. The next maximum signal is detected at the position $X$.
The distances between each of the two slits, $S_{1}$ and $S_{2}$ and the microwave receiver when the aerial is in position $\mathrm{X}$ are $\mathrm{S}_{1} \mathrm{X}=$ $0.3335 \mathrm{~m}$ and $\mathrm{S}_{2} \mathrm{X}=0.3615 \mathrm{~m}$
Find the wavelength of the microwave and select the two correct reasons that explain why the signal strength falls to a minimum between $U$ and $V$, and between $V$ and W.
Post time 2024-1-26 22:03:40