[填空题]
The radius of a circle of g090 b27lh52js,yfptebxx jt77bfkh wire )gts.:(f;he 7is5;n jiyr*qm ogt i l*mc 2bn)is measured to be 10.0 ± 0.5 cm. What is the percentage error in the area of the loop? % What is the percentage error in the circumference of the loop? %
参考答案: 空格1: 10.0
空格2: 5.0
本题详细解析: First calculate the percentage error in the radius xmcn3g -lv0-gof the loop: $$ \frac{\Delta \mathrm{r}}{\mathrm{r}}=\frac{0.5}{10}=5 \% $$ The area of a circle is $A=\pi r^2$ and so the percentage error on the area of the loop will be twice the percentage error of the radius, $\Delta A=10 \%$.