[填空题]
The potential differ z5e lp26:xqspe wkf)(f g0kgf8on4 tok1-rz:t r a4xd1nce ($V$) across a resistor is measured with a digital voltmeter to be $0.10 \; V$ . What is the percentage uncertainty in $V^2$ ? % (please only input numerical value without units and without the $\pm$ symbol.)
参考答案: 20.00
本题详细解析: The voltmeter is a digital device and so the uncertainty is w )by(neawp6x bqp.9k-m9 r(athe smallest value which i.9(rpk9pw)y6na - qw (babmext can record, $0.01 \mathrm{~V}$. This is a $10 \%$ uncertainty on the $0.10 \mathrm{~V}$ measurement. The uncertainty in $V^2$ will be twice this, giving $20 \%$.