[填空题]
The potential differenca3b2 x 98qbibd50qs8o6gv nmge (pmk1*: 4lt *n,4ea lmr h91rztj f)iejw8q j1s$V$) across a resistor is measured with a digital voltmeter to be $0.10 \; V$ . What is the percentage uncertainty in $V^2$ ? % (please only input numerical value without units and without the $\pm$ symbol.)
参考答案: 20.00
本题详细解析: The voltmeter is a digital device and so the uncertainty)fr:zu 98 mwyv is the smallest value which it can rervw89u y)m:fz cord, $0.01 \mathrm{~V}$. This is a $10 \%$ uncertainty on the $0.10 \mathrm{~V}$ measurement. The uncertainty in $V^2$ will be twice this, giving $20 \%$.
Post time 2024-8-21 21:38:19